Sampling Distribution Basics
Sample Proportions
Sample Means
Central Limit Theorem
Sampling Distribution Problems
100

The distribution of a statistic (like the mean or proportion) over all possible samples of a given size from a population

What is a sampling distribution?

100

p, the population proportion

What is the mean of the sampling distribution of the sample proportion p^?

100

μ, the population mean is the center of this

What is the mean of the sampling distribution of the sample mean xˉ?

100

What does the Central Limit Theorem (CLT) state?

The sampling distribution of the sample mean becomes approximately normal as the sample size increases

100

You sample 50 people from a population with p = 0.6. What's the expected value of p^?

0.6

200

The population mean, μ

What is the center (mean) of a sampling distribution of a sample mean?

200

Square root of [(p(1-p))/n], assuming conditions are met

What is the standard deviation formula of the sampling distribution of p^?

200

σ/(square root of n)

What is the standard deviation of xˉ when sampling from a population with standard deviation σ?

200

What sample size is typically considered large enough for the CLT to apply?

30 or more

200

A population is skewed right. You take a random sample of size 40. Can you use a normal model to describe the sampling distribution of the sample mean? Why or why not?

Yes, because the sample size is large enough (n ≥ 30) for the Central Limit Theorem to apply.

300

As sample size increases, the sample mean get closer to the population mean.

What does the Law of Large Numbers say about sample means as sample size increases?

300

Make sure these are met: 1) Random sample

 2) np≥10 np≥10 and n( 1 − p)≥10 n(1−p)≥10

What are two conditions that must be met to use the normal model for p^?


300

Under what conditions is the sampling distribution of the sample mean approximately normal?

If the population is normal or n≥30

300

Why is the CLT important in statistics?

It allows us to use normal probability formulas even when the population distribution is not normal.

300

In a random sample of 100 people, 60% say they like pineapple on pizza. Assuming the population proportion is 0.6, what is the standard deviation of the sampling distribution of p^?

Square root of [(0.6)(0.4)/100] = 0.049

400

Increasing sample size decreases the variability.

How does increasing the sample size affect the variability of a sampling distribution?

400

What is the standard deviation of p^, for population proportion, p= 0.4 and you take a random sample of size 100?

This calculation, population proportion p for this calculation, and n the sample size: square root of [(0.4)(0.6)/100] = 0.049 


400

A population has a mean of 50 and a standard deviation of 10. What is the standard deviation of the sample mean for samples of size 25?

10/(square root of 25) = 2

400

For a population with mean 100 and standard deviation 20, what would be the approximate shape of the sampling distribution of the mean for n=40?

Approximately normal. (40≥30, CLT suggests approximately normal)

400

In a quality check, a sample of 64 batteries has an average charge of 98 hours. Population mean is 100, SD is 8. What's the probability of getting a sample mean this low or lower?

z = (98−100)/(8/square root of 64) = −2

 P(Z < -2) ≈ 0.0228

500

The sample size must be large (n≥30) because the population distribution does not meet the Normal condition

What the Central Limit Theorem?

500

The Central Limit Theorem

Why we say the sampling distribution of p^ is approximately (n > = 30 ) normal even if the population distribution is not?

500

The shape of the sampling distribution of xˉ of the population is heavily skewed and n=10 ?

What is a likely skewed and not approximately normal (sample size is too small for CLT)


500

A population is right-skewed with mean 60 and standard deviation 12. What can we say about the distribution of the sample mean for samples of size 50?

Approximately normal. (50≥30, CLT suggests approximately normal)

500

A population has a mean of 75 and a standard deviation of 20. What is the probability that a sample of size 36 has a mean greater than 80?

σxˉ = 20/square root of 36 = 3.33

z = (80-75)/3.33 ≈ 1.5

P(xˉ>80) = P(Z>1.5) ≈ 0.0668