If AB = 5 and BC = 7, what is AC?
AC=5+7=12
What is the formula for the midpoint of two points (x1, y1) and (x2, y2)?
("Midpoint Formula:") ((x_1 + x_2)/2, (y_1 + y_2)/2)
What is the sum of complementary angles?
90∘
Name a pair of corresponding angles. *See Board*
Any pair of angle in the same relative position
The sum of interior angles in a triangle is ___.
180∘
If ∠ABC=50∘ and ∠CBD=40∘, what is ∠ABD?
angle(ABD) = 50^@ + 40^@ = 90^@
What is the distance between (2,3) and (6,7)?
d = sqrt((6-2)^2 + (7-3)^2) = sqrt(16 + 16) = sqrt(32) = 4sqrt(2)
If two angles are supplementary and one is 60∘, what is the other?
180∘−60∘=120∘
Alternate interior angles are always ____.
Congruent
What is the exterior angle theorem?
The exterior angle is equal to the sum of the two remote interior angles.
Given that AB+BC=AC, solve for x if AB=2x+3, BC=x+5, and AC=16.
x=8/3
A triangle has legs of 6 and 8. What is the hypotenuse?
c = sqrt(6^2 + 8^2) = sqrt(36 + 64) = sqrt(100) = 10
Two vertical angles are represented as (3x+10)∘ and (5x−20)∘. Find x.
3x + 10 = 5x - 20 => x = 15
If a transversal creates one angle of 70∘, what is the corresponding angle?
70∘ (corresponding angles are equal)
Find the missing angle: 40∘, 60∘, and ___.
180 - (40 + 60) = 80^@
The measure of ∠XYZ is 4x+10 and ∠WYZ is 2x+20. If ∠XYZ+∠WYZ=90∘, find x.
x=10
The midpoint of A(3, 7) and B(x, 9) is (5, 8). Find x.
(3 + x)/2 = 5 => 3 + x = 10 => x = 7
Angle A and Angle B are complementary. If Angle A is twice the measure of Angle B, find both angles.
A + B = 90^@ and A = 2B => 2B + B = 90 => B = 30^@, A = 60^@
Two parallel lines are cut by a transversal. If one alternate exterior angle is 110∘, what is the other?
110∘
If an exterior angle is 120∘ and one interior angle is 50∘, find the other interior angle.
120 = x + 50 => x = 70^@
M is the midpoint of AB. If AM=3x−2 and MB=2x+6, find AB.
AB=28
A right triangle has legs of 5x and 12x, and its hypotenuse is 13x. Find x.
(5x)^2 + (12x)^2 = (13x)^2 => 25x^2 + 144x^2 = 169x^2
, so x can be any real number.
If ∠1=(x+20)∘ and ∠2=(2x−10)∘, and they are vertical angles, find x.
x + 20 = 2x - 10 => x = 30
Solve for x if a corresponding angle is (2x+10)∘ and another is (4x−20)∘.
2x + 10 = 4x - 20 => x = 15
Find x if the angles of a triangle are (2x+10)∘, (3x−20)∘, and (x+30)∘.
(2x + 10) + (3x - 20) + (x + 30) = 180 => 6x + 20 = 180 => x = 40