GOF
Homogeneity
Association/ Independence
Hypotheses
Calculations
100

The three conditions for a chi-square GOF test are:

Random, Independence, and Chi-square distribution

100

How do you check the Random condition for a chi-square test?

Use a stratified random sample or a randomized experiment.

100

These two chi-square tests both start with a two-way table.

Chi square test for homogeneity as well as the test for association/independence 

100

When completing a chi square test we test for/against the null. 

We test against the null hypothesis. 

100

What is the equation for testing Independence? 

10% condition

n</= (.10)N

200

Chi-square statistic is used to measure what?

How far expected counts are from observed counts. 

200

What variables do you compare when concluding a chi-square test for homogeneity. 

Compare p-value and alpha. 

200

Chi-square test for association/Independence is ran nearly identical to what other chi-square test? 

Chi-square test for homogeneity. 

200

Null hypothesis for GOF. 

The claimed distributions are correct. 

200

What criteria must be met to pass the Chi-square distribution condition?

All expected counts are greater than or equal to 5.

300

Describe the Chi-square distribution.

It is not a normal distribution, it is right skewed, and only allows for positive values. 

300

What are the two parts of a chi-square test for homogeneity?

Overall test to see if there is convincing evidence to support a hypothesis and the follow up analysis to decide which parameters differ and by how much.

300

What does the chi-square test for association/independence test for?

Weather two categorical variables are associated in one population.

300

Alternative hypothesis for GOF 

At least 1 of the claimed proportions is incorrect. 

300

What calculator function is used to find p-value?

 Chi-square cdf (upper, lower, df)

400

If p-value is less than alpha, do you accept the null, and what is this known as?

No, reject the null, this is known as Power.
400

T or F- when determining expected counts we assume the null is correct. 

True 

400

What three values does both chi-square test for homogeneity and association/independence solve for?

Chi-squared, degrees of freedom, and p-value

400

Null hypothesis for Chi-square test for homogeneity. 

There is no difference in the distribution of proportions.

400

What is the equation for expected counts?

(row total)*(column total)

         Over all total

500

Chi- square test for Association/Independence is used to study what type of relationship?

The Relationship between two categorical variables across a single population.

500

Chi-square for homogeneity test allows us to compare what?

The proportions of success in 1 or 2 populations with 2 proportions. 

500

What relationship is studied in chi-square test for Association/independence?

The relationship between 2 categorical variables and a single population. 
500

Null hypothesis for Association/Independence 

There is no association between the two variables. The two variables are independent.   

500

What is the equation for a chi-square statistic?