2 KClO3 --> 2 KCl + 3 O2
How many moles of O2 will be formed from 1.65 moles of KClO3?
2.48 moles
2 KClO3 --> 2 KCl + 3 O2
How many grams of O2 will be produced from 3 moles of KClO3
144g
2 KClO3 --> 2 KCl + 3 O2
How many moles of KClO3 will be need to produce 44 grams of O2
4 Fe + 3 O2 --> 2 Fe2O3
How many grams of O2 are needed to react with 125 grams of Fe?
53.7g
4 Fe + 3 O2 --> 2 Fe2O3
What is the limiting reactant in a reaction with 5 moles Fe and 7 moles of O2
Fe
2 KClO3 --> 2 KCl + 3 O2
How many moles of KClO3 are needed to make 3.50 moles of KCl?
3.5 Moles
2 KClO3 --> 2 KCl + 3 O2
How many grams of KClO3 will be produced from 7 moles of O2?
571.7g
2 KClO3 --> 2 KCl + 3 O2
How many moles of O2 will be produced from 372 grams of KClO3
4.56 Moles
2 KClO3 --> 2 KCl + 3 O2
How many grams of O2 will be formed from 3.76 grams of KClO3?
1.47g
2 KClO3 --> 2 KCl + 3 O2
What is the Percent yield in a reaction that produced 3 moles of O2 and used 200g of KClO3
81.6%
4 Fe + 3 O2 --> 2 Fe2O3
How many moles of Fe2O3 are produced when 0.275 moles of Fe are reacted?
0.138 Moles
4 Fe + 3 O2 --> 2 Fe2O3
How many grams of Fe2O3 will be produced from 4 mol of O2
425.6g
4 Fe + 3 O2 --> 2 Fe2O3
How many moles of Fe were needed to produce 432 grams of Fe2O3
5.4 grams
2 KClO3 --> 2 KCl + 3 O2
How many grams of KCl will be formed from 2.73 g of KClO3?
1.66 g
4 Fe + 3 O2 --> 2 Fe2O3
What is the percent yield in a reaction that produced 159 grams of Fe2O3 and used 55 grams of O2
86.9%
4 Fe + 3 O2 --> 2 Fe2O3
How many moles of Fe2O3 are produced when 31.0 moles of O2 are reacted?
20.7 Moles
4 Fe + 3 O2 --> 2 Fe2O3
How many grams of Fe will be needed to produce 7 moles of Fe2O3
781.2g
4 Fe + 3 O2 --> 2 Fe2O3
How many moles of O2 were needed to produce 142 grams of Fe2O3
1.33 moles
4 Fe + 3 O2 --> 2 Fe2O3
How many grams of Fe2O3 are produced when 17.0 grams of O2 is reacted?
56.6g
4 Fe + 3 O2 --> 2 Fe2O3
What is the percent yield in a reaction that produced 120 grams of Fe2O3 and used
71.9%
4 Fe + 3 O2 --> 2 Fe2O3
How many moles of O2 are needed to react with 8.9 moles of Fe?
6.7 Moles
2 C4H10 + 13 O2 --> 8 CO2 + 10 H2O
How many grams of C4H10 will be needed to produce 5 moles of CO2
72.5g
2 C4H10 + 13 O2 --> 8 CO2 + 10 H2O
How many moles of H2O would be produced from 79 grams of C4H10
6.8 moles
2 C4H10 + 13 O2 --> 8 CO2 + 10 H2O
How many grams of CO2 are produced from the combustion of 100. grams of butane?
303g
2 C4H10 + 13 O2 --> 8 CO2 + 10 H2O
What is the percent yield in a reaction that produce 300 grams of CO2 and used 111 grams of C4H10
89.1%