jennifer
What is Jennifer's favourite colour?
blue.
What is Jasper's favourite thing to say when meeting someone for the first time?
Hello I am Jasper
If Lucia could commit any crime with no punishment, what crime would she do?
Theft
Gabby said the answer to a multiplication problem is a quotient. Melanny said the answer to a multiplication problem is a product. Who is correct?
Logan
What is Fisher's favourite type of cuisine?
Mexican
What is Jennifer's favourite movie?
Project Sekai Colorful Stage Featuring Hatsune Miku The Movie: Colorful Stage! The movie: A Miku Who Cant Sing
What is Jasper's zodiac sign? (Bonus points if you guess his birthday!)
Libra / October 19
What is Lucia's favourite card game?
Blackjack
What African country was formerly known as Zaire?
The Democratic Republic of The Congo
If Fisher could be any animal, what would he be?
purple lizard
What's the first show Jennifer watched as a wee little lad?
What is Jasper's favourite food?
Teleportation
What are the names of Cinderella's stepsisters?
Anastasia and Drizella
Christian Rock
What area of China is Jennifer from?
Guangdong province/Southeast China
If Jasper had a billion dollars, what would they do with it?
hire an assassin to kill fisher
What other countries outside the US has Lucia been to? (hint: europe)
None
Prove that (√2+ √3+ √5) is irrational
Start by saying that it is rational. That is, s is a rational number. Square it. s^2 is also rational.
s = (sqrt(2) + sqrt(3) + sqrt(5))
s^2 = 2 + 2 * sqrt(2) * (sqrt(3) + sqrt(5)) + (sqrt(3) + sqrt(5))^2
s^2 = 2 + 2 * sqrt(2) * (sqrt(3) + sqrt(5)) + 3 + 2 * sqrt(3 * 5) + 5
s^2 = 2 + 3 + 5 + 2 * sqrt(6) + 2 * sqrt(10) + 2 * sqrt(15)
s^2 = 10 + 2 * (sqrt(6) + sqrt(10) + sqrt(15))
(s^2 - 10) / 2 will also be rational, so we need to only focus on the remaining bit. If s was rational, then this remaining bit should also be rational. Call it a and do the same trick again.
a = sqrt(6) + sqrt(10) + sqrt(15)
a^2 = 6 + 2 * sqrt(6) * (sqrt(10) + sqrt(15)) + (sqrt(10) + sqrt(15))^2
a^2 = 6 + 2 * sqrt(60) + 2 * sqrt(90) + 10 + 2 * sqrt(150) + 15
a^2 = 6 + 10 + 15 + 2 * (2 * sqrt(15) + 3 * sqrt(10) + 5 * sqrt(6))
a^2 = 31 + 2 * (5 * sqrt(6) + 3 * sqrt(10) + 2 * sqrt(15))
a^2 = 31 + 2 * (2 * (sqrt(6) + sqrt(10) + sqrt(15)) + 3 * sqrt(6) + sqrt(10))
a^2 = 31 + 2 * (2a + 3 * sqrt(6) + sqrt(10))
(a^2 - 31) / 2 - 2a will also be rational, since a is rational. Now say that 3 * sqrt(6) + sqrt(10) = b and if our original assumptions were correct, then b must also be rational.
b = 3 * sqrt(6) + sqrt(10)
b^2 = 9 * 6 + 6 * sqrt(6) * sqrt(10) + 10
b^2 = 54 + 10 + 6 * sqrt(60)
b^2 = 64 + 6 * 2 * sqrt(15)
b^2 = 64 + 12 * sqrt(15)
(b^2 - 64) / 12 = sqrt(15)
Now we know that (b^2 - 64) / 12 should be rational if s was rational. So the real question here is this: Is sqrt(15) rational?
There are plenty of proofs online that demonstrate that sqrt(15) is irrational. So, because sqrt(15) is irrational, then that means we have our contradiction. And it goes all the way back to the assumption that s is rational. Since s is irrational, then sqrt(2) + sqrt(3) + sqrt(5) is also irrational.
If Fisher could go anywhere in the world, where would he go?
New Jersey/Cuba
How much money has Jennifer spent on Project Sekai?
~$319
8,192
What is the strangest thing Lucia has ever eaten?
Bean boozled jellybean
What is Julie's favourite (country) flag? (3 answers so its a little easier)
Eswatini/Kenya/Grenada
what is fishers blood type
green