Calculate ΔHrxn from standard enthalpies of formation
Estimate ΔHrxn from bond energies
Stoichiometry involving enthalpy
Calculate the change in internal energy ΔU
Challenge Problems
100

\iven the following reaction and standard enthalpy values, find ΔHrxn: 

2H2(g)+O2(g)→2H2O(l)

  • ΔH°f [H₂O(l)] = −285.8 kJ/mol

  • ΔH°f [H₂(g)] = 0

  • ΔH°f [O₂(g)] = 0

ΔHrxn = -571.6 kJ

100

Use the average bond energies on the CH122 equation sheet to estimate

the ΔHrxn for the following reaction:

a. N2 + 3 H2 → 2 NH3

Hrxn = -86 kJ/mol

100

Consider the following reaction:

2 NO2 (g) ➝ N2O4 (g) ΔHrxn: -57.23 kJ/mol

What mass of NO2 must react for the reaction to release 450.0 kJ of heat?

723.55 g NO2

100

A system that absorbs 562 J of heat and has 23 J of work done on it

585 J

100

How much heat is produced when 100 mL of 0.250 M HCl (density, 1.00 g/mL) and 200 mL of 0.150 M NaOH (density, 1.00 g/mL) are mixed? 

HCl (aq) + NaOH (aq) --> NaCl (aq) + H2O (l)

ΔH = - 58 kJ/mol

-1.45 kJ

200

Calculate Hrxn:

CH4(g)+2O2(g)→CO2(g)+2H2O(g)

Given:

  • ΔH°f [CH₄(g)] = −74.8 kJ/mol

  • ΔH°f [CO₂(g)] = −393.5 kJ/mol

  • ΔH°f [H₂O(g)] = −241.8 kJ/mol

  • ΔH°f [O₂(g)] = 0

-802.3 kJ

200

Use the average bond energies on the CH122 equation sheet to estimate the ΔHrxn for the following reactions:

2 H2O → 2 H2 + O2


Hrxn = +486 kJ/mol

200

C2H4(g) + H2(g) → C2H6(g)  ΔH=−137 kJ

Question:
What mass of C₂H₆ is produced when 411 kJ of heat is released?

90.2 g

200

A system that releases 84 J of heat and has 496 J of work done on it

412 J

200

C2H4 + 6F2 ⟶ 2CF4 + 4HF

Find the △H of the above reaction given:

H2 + F2 ⟶ 2HF     △H = -537 kJ

2C + 2H2 ⟶ C2H4   △H = +52 kJ

CF4 ⟶ C + 2F2   △H = +680 kJ

-2486 kJ

300

Find Hrxn: 

2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(s)

Given:

  • ΔH°f [Al₂O₃(s)] = −1675.7 kJ/mol

  • ΔH°f [Fe₂O₃(s)] = −824.2 kJ/mol

  • ΔH°f [Al(s)] = 0

  • ΔH°f [Fe(s)] = 0

-851.5 kJ

300

Use the average bond energies on the CH122 equation sheet to estimate the ΔHrxn for the following reactions:

CH4 + H2O → CO + 3 H2


Hrxn = +200 kJ/mol

300

Calculate Hrxn from the following equation:

2SO2(g) + O2(g) → 2SO3(g)  ΔH=−198 kJ

Given:

  • 25.0 g SO₂

  • 10.0 g O₂

Hrxn = -38.61 kJ

300

A system that absorbs 512 J of heat and does 715 J of work

-203 J