A wipe test swab produces a gross count of 1500cpm in a well counter with 56% efficiency. The background is 400cpm. Calculate the dpm produced by the swab.
1500cpm-400cpm/(0.56)= 1964dpm
Precision = _________________
30,000-300 / 150= 198
Formula: Source cpm- background cpm / source activity
.693/6hr= .115
(Thyroid counts- Thigh counts) / [ (Capsule -background)x decay factor] x 100%
What is the exposure rate at 1cm from an unshielded 30mCi dose of Tc99m. The exposure constant is 0.59Rcm2/mCi(h) at 1cm.
(30mCi)/(1cm)2 x 0.59Rcm2/mCi(h) = 17.7R/h
*** Note: Please watch your units!!! ***
Acccuracy=__________________
True Value
if a 128 x128 matrix is selected, how many pixels?
128 x128 = 16.384 pixels
A vial of DTPA is reconstituted with 100mci of Tc-99m. What will its activity be 4 hours later?
100mCi x e-.693x (4hr/6hr) = 63mci
Formula for LVEF
%EF = NET ED COUNTS - NET ES COUNTS/ NET ED COUNTS.x 100%
If you are exposed to a source for 4hours(why!?.. please don't ever be) what is the total radiation dose? The exposure rate of the source is 0.5mrem/hr?
(0.5mrem/hr) x 4hr = 2mrem
Formula: Total Dose = (dose rate)(time)
Calculate the 10% acceptable range for
195uci
195 *.10 = 19.5
Range = 195-19.5 =175.5
195 + 19.5 = 214.5
(256pixels x 256 pixels) / (128pixels x 128 pixels) = 65,536/ 16,384 pixels = 4 frames
Please use Clark's Formula
Clark's Formula: 30lb x 20mCi / 150lb = 4mci
If a source produces an exposure rate 350mrem/h at 3 inches from the surface, what is the exposure rate at 40inches.
350mrem x (3in)2 = I x (40in)2
=1.97 mrem
l 1.5mCi-1.1mCi l / (1.5mCi) x100% = 27%
How much memory is required for a 60-frame study using 64 x64 byte mode if the data are also stored in byte mode?
64 x 64x 60= 245,760
(80 x 6 )/ 150= 3.2mCi
****** DAILY DOUBLE ******
What does ALARA stand for?
As Low As Reasonably Achievable
Calculate the correction factor for the 5uci dose level if the expected value is 10uci and the actual value is 12uci.
10/12= 0.83
Correction Factor = expected activity/ actual activity**** DAILY DOUBLE ****
A 1,000,000 count SPECT study is to be performed on a phantom that produces a counting rate of 100,000cpm. If the acquisition is to have 62 stops over 360degree. What will be the total acquisition time, time per stop, and counts per stop?
Acquisition time: 1,000,000counts/100,000cpm = 10mins
Time per Stop: 10 min /62 stops = .16 min/stop
Counts Per Projection: 1,000,000/ 62 stops = 16,129counts/stop
If a generator yields 500mCi when 600mci of Tc are actually present on the column, what is its percent efficiency?
500/600 x100= 83%