Write the eq of the line with slope 8 and y-intercept 5.
y = 8x + 5
m = 8 passing through (3,4)
y - 4 = 8(x - 3)
y - 2 = 3x + 5
3x - y = -7
(9,3) (10, -7)
m = -10
m = -9 (-2,1)
Point-slope form
y - 1 = -9(x + 2)
Write the eq of the line with slope 2 and passing through (0,7)
y = 2x + 7
m = -2 passing through (-4,5)
y - 5 = -2(x + 4)
y = -9x + 7
9x + y = 7
y = 4x + 5
m = 4
m = 7 (0,4)
Slope-intercept
y = 7x + 4
Passing through (9,1) and (0,3)
y = -2/9x + 3
Point in y - 7 = 4(x - 6)
(6,7)
y - 2 = 3/5(x + 1)
3x - 5y = -13
y - 5 = 3(x + 6)
m = 3
m = 4 (3,1)
Standard form
4x - y = 12
slope = 5 passing through (7,-1)
y = 5x - 36
Slope in y - 8 = -5(x + 3)
m = -5
y = 1/3x + 4
x - 3y = -12
5x + 7y = 21
m = -5/7
(2,1) (3, 5)
Slope-intercepty = 4x - 7
slope = -2 passing through (1,-5)
y = -2x -3
Passing through (-8,2) and (-9, 5). Use the first point when writing the equation.
y - 2 = -3(x + 8)
m = 4 passing through (0,3)
4x - y = -3
(8,4) (8, 7)
undefined
(8,2) (9, 10)
Standard form
8x - y = 62