Find the derivative of:
f(x)=5x^3-4/x
f'(x)=15x^2+4/x^2
Where does this function appear to be non differential?
x= -1 and x = 6
Find the average velocity of the function below from t = 0 to t = 4.
-1/2
Write the equation of the tangent line at x = 9 for
y=5sqrtx
y-15=5/6(x-9)
Given f(2)=3, f'(2)=1, g(2)=-2, and g'(2)=-5. Determine the value of p'(2)
p(x)=3f(x)g(x)
p'(2)=-51
For what values of x is the function not differentiable?
y=|2x-9|
x = 9/2
Given the velocity graph, when does the object change directions?

t = 4
Becuase velocity changes signs.
What is the average rate of change of the function below from t = 1 to t = 3?
g(x)=4x^2-pi
16
Find the derivative of
y=(7x^4+3x^2-4)/x^2
y'=14x+8/x^3
Determine if the function is differentiable at x = -1.
It is not, because it is not smooth.
The function below models the position of a particle for time greater than or equal to zero. When is the velocity zero?
x(t)=t^3/3+t^2/2-6t+1
t=2
What is the derivative of the function below?
k(x)=1/f(x)
k'(x)=-(f'(x))/f^2(x)
Find the second derivative of
y=2/x+6sqrt(x)
y''=4/x^4-3/(2x^(3/2))
For what value of a and b will this function be differentiable at x = 1

a = 1/2 and b = -1/2
Given the velocity graph, when is the particle speeding up?
(0, 1), (4,5), and (7,9) because velocity and acceleration have the same signs on those intervals
For what value(s) of x would the function below have an instantaneous rate of change of -2?
y=x/(x-2)
x = 1 and x = 3