Substitution
Solve for x
Name the Mistake
Exponents 1
Exponents 2
100

5x

x=3

15

100

b3(bx) = b7

4

100

xx= x35

Multiplied exponents

x12

100

xxx5

x12

100

(1/3)2

1/9

200

3 + 4a

a=-5

-17

200

(b5)= b40

8

200

(24)(34) = 64

Multiplied bases and kept exponents

1,296

200

xy/ xy4

xy5

200

(7x3y5)2

49x6y10

300

xy - y

x=3, y=-4

-8

300

2= 0.125

-3

300

4+ 4= 45

Used the multiplication law on addition

80

300

2+ 32

25

300

-8(xy3)0

-8

400

7y+ 2y

y=-2

-60

400

b/ b= b9

-6

400

(5b2)(2b6) = 7b8

Added coefficients, rather than multiplied

10b8

400

(35)8

340

400

(x/ 2y-3)-5

32/x20y15

500

a - 2ab + b2

a=-3, b=-5

-26

500

(b/ b6)= b35

11

500

(5xyz0)= 5x8y24

Didn't apply the exponent 4 to the coefficient

625x8y24

500

(92)(94)5

926

500

(6 xy) (7 xy2) / 3x13 y3

14/x3

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