500
In a population of 150 hummingbirds, 25 are homozygous dominant (AA), 75 are heterozygous (Aa), and 50 are homozygous recessive (aa). What is the frequency of the dominant allele F(A)? What is the frequency of the recessive allele F(a)?
2(# of AA ind) + (# of Aa ind)/ total number of alleles = F(A)
(2(25) + (75))/300 alleles= .41= F(A)
1-.41=.59=p or F(a)