Factor into two binomials:
x2+10x+25
(x+5)(x+5)
Factor
2x2-7x+6
(2x-3)(x-2)
Factor:
3x2-12x
3x(x-4)
Factor completely:
a2b2-144a2
a2(b+12)(b-12)
Factor:
x2-16
(x+4)(x-4)
Factor into two binomials:
x2-12x+27
(x-9)(x-3)
Factor
9x2+6x+1
(3x+1)(3x+1)
Factor:
x5-x3
x3 (x2-1)
Factor completely:
x4-81
(x+3)(x-3)(x^2+9)
Factor:
9-x2
(3+x)(3-x)
Factor into two binomials:
x2+2x-24
(x+6)(x-4)
Factor
2x2-x-6
(x-2)(2x+3)
Factor:
y3+2y
y (y2+2)
Factor completely:
y4-2y2-63
(y2+7)(y+3)(y-3)
Factor:
25y2-4k2
(5y+2k)(5y-2k)
Factor into two binomials:
x2-5x+6
(x-3)(x-2)
Factor
4y2+12y+9
(2y+3)(2y+3)
Factor:
4ab2-12a2b
4ab(b-3a)
Factor completely: 2x3+14x2-60x
2x(x+10)(x-3)
Factor:
4x2-49
(2x-7)(2x+7)
Factor into two binomials:
y4-7y2-18
(y2-9)(y2+2)
For an extra 50 points can you factor it completely?
Factor:
2x4+x2-6
(x2+2)(2x2-3)
Factor:
x2-4x4
x2(1-4x2)
Factor completely:
80-5d2
5(4+d)(4-d)
Factor:
x2+100
Can not be factored because of the plus sign.
For a bonus 50 points: What type of solutions would this create?