Literal Equations
Solve for a
ax + y = g
a = (g-y)/x
or
a = g/x - y/x
Graph and state the interval notation:
x<= -6
(-infinity, -6]
State the slope intercept form for a line with a
slope = 3 and y-intercept = (0, -4)
y = 3x-4
State whether each below are Linear or Quadratic:
a) 5(x2 - 3) = 2x + 4
b) 4 - 3x + 7 = 2(x - 3)
c) 13 = 5x2 + 7
a) Quadratic
b) Linear
c) Quadratic
Solve:
5y2 - 45 = 0
Solution: y = 3, -3
Solve for w
P = 2L + 2W
Graph and state the interval notation:
x > -3
Graph:
(-3, infinity)
State the slope and y-intercept for the following:
y = 2/3 x + 9
slope: 2/3
y-intercept: (0,9)
Solve:
4x - 3 = 7 - 2(2x + 5)
Solution: All real numbers
Solve
x2 - 5x + 4 = 0
Solution: x = 4, 1
Solve for y
6x + 3y = 15
y = -2x + 5
Solve and write your solution in interval notation:
2x - 6 > 18
(12, infinity)
State the slope and y-intercept for the following:
y = -5/3 x -7
slope = -5/3
y intercept: (0, -7)
Explain when to use the square root method and the zero product property when solving an equation.
When you have a quadratic equation, we use the square root method when there is not a bx term. If there is a bx term we use zero product (factoring).
Solve:
2y + 5(3y - 1) = 6 + 3y + 6y - 7
Solution: y = 1/2
Solve for y
-5x - 4y = 28
y = -5/4 x - 7
Solve and write your solution in interval notation:
3x + 7 >= 5x - 1
( -infinity, 4]
Write the slope intercept form for a line with a
slope =0 and y-intercept = (0, -2)
y= -2
Solve:
2x2 + 16x = 0
Solution: x = 0 and x = -8
Solve:
6x2 = 42
x = - sq root (7), sq root (7)
Solve for y
4x - 6y + 12 = 0
y = 2/3 x + 2
Solve and state the solution in interval notation.
6(x + 3) < 4 - 2(x + 5)
(-infinity, -3)
State the slope and y-intercept for the following:
3x - 4y = 20
slope = 3/4
y-intercept: (0, -5)
Solve:
1/2x - 3 = 2 (1/4x + 6)
Solution: No Solution
Solve:
3x2 + x = 10
Solution: x = 5/3, -2